Answer:
y = 5x -15
Step-by-step explanation:
slope/y-int from = y =mx+b
slope = y2-y1/x2-x2
slope = 0--15 / 3-0
slope = 15 / 3
slope = 5
y-int = -15
y = 5x-15
Answer: C
<u>Step-by-step explanation:</u>
The general form of the equation is: g(x) = a|x - h| + k ;
- "a" represents the vertical stretch <em>(or shrink)</em>
- "h" represents the x-coordinate of the vertex (left and right)
- "k" represents the y-coordinate of the vertex (up and down)
4 units left means h = 4
2 units up means k = 2
--> g(x) = |x - 4| + 2
Answer:
25/11 divided by 5/22 = 10
Step-by-step explanation:
Step 1:
Start by setting it up with the divisor 11 on the left side and the dividend 25 on the right side like this:
1 1 ⟌ 2 5
Step 2:
The divisor (11) goes into the first digit of the dividend (2), 0 time(s). Therefore, put 0 on top:
0
1 1 ⟌ 2 5
Step 3:
Multiply the divisor by the result in the previous step (11 x 0 = 0) and write that answer below the dividend.
0
1 1 ⟌ 2 5
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (2 - 0 = 2) and write the answer below.
0
1 1 ⟌ 2 5
- 0
2
Step 5:
Move down the 2nd digit of the dividend (5) like this:
0
1 1 ⟌ 2 5
- 0
2 5
Step 6:
The divisor (11) goes into the bottom number (25), 2 time(s). Therefore, put 2 on top:
0 2
1 1 ⟌ 2 5
- 0
2 5
Step 7:
Multiply the divisor by the result in the previous step (11 x 2 = 22) and write that answer at the bottom:
0 2
1 1 ⟌ 2 5
- 0
2 5
2 2
Step 8:
Subtract the result in the previous step from the number written above it. (25 - 22 = 3) and write the answer at the bottom.
0 2
1 1 ⟌ 2 5
- 0
2 5
- 2 2
3
You are done, because there are no more digits to move down from the dividend.
The answer is the top number and the remainder is the bottom number.
Therefore, the answer to 25 divided by 11 calculated using Long Division is:
Problem One
Remark
If she doesn't mind having I kg left over, the minimum number would be 3 five kg boxes. If on the other hand, she must have exactly 14 kg then the minimum number is 6.
She needs 2 five kg boxes and 4 one kg boxes. <<<< Answer
Problem Two
There is a method of solving this that is called dimensional analysis. It is what should be used here. I'll do it at the end of the problem. In the meantime, you have to do it a slightly longer way.
1 portion = 100 grams.
x portions = 1kg which is 1000 grams.
x portions = 1000 grams.
Set up a proportion to find the number of servings in 1 kg
1 portion/x = 100 grams/1000 grams Cross multiply
1 * 1000 = 100 * x Divide by 100
1000/100 = x
x = 10 servings in 1 kg.
So each kg produces 10 portions
1 kg / 10 portions = 20 kg / x portions Cross multiply
x * 1 = 10 * 20
x = 200 portions <<<<< Answer
Dimensional Analysis
[1batch]*[1 portion/100g][1000g/kg][20kg/batch] the units cancel
1000 * 20 / 100 only the portions are left over.
200 portions is the answer.
Problem Three
1 kg = 1000 grams
x kg = 5000 grams Cross multiply
1*5000 = 1000 x
x = 5 kg
1 parcel weighs 5 kg
x = 15 kg
15 kg = 5 x
x = 15/5
x = 3
So he can carry 3 parcels per trip.
Since there are 5 such parcels, he will have to make 2 trips. The second one will not be a full load.
First Trip = 3 parcels
Second Trip = 2 parcels. <<<<Answer
Slope of f(x) = (-3 - (-6)) / (0- (-1) = 3 / 1 = 3
Check with second and third points ; - slope = (0 -(-3) / (1 - 0) = 3/1 = 3
slope of g(x) = the coefficient of x which is 4.
