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3 years ago

I NEED HELP WITH THE TOP ONE ON THE RIGHT!

Mathematics

2 answers:

alexandr402 [8]3 years ago

7 0

Answer:

A. y = 2/5x - 2

Step-by-step explanation:

We can use the slope formula to find the slope of the line.

$m=\frac{y_1-y_2}{x_1-x_2} \\m=\frac{-2-0}{0-5} \\m=\frac{-2}{-5}\\m=\frac{2}{5}$

Now we know that the slope of the line is 2/5. By looking at the graph, the line crosses the y-axis at the point (0, -2). Therefore, the equation of the line is y = 2/5x - 2.

OLEGan [10]3 years ago

4 0

Y=2/5x-2 is what I think the answer is. I agree with the person above

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Vitek1552 [10]

Answer:

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Step-by-step explanation

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3 years ago

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svp [43]

Answer:

The error in the argument is in assuming that the line from p to d passes through line ab - that is, that pd crosses below a. But actually pd passes above a. This means that the angle pad is not equal to x + pab, but rather angle pad = 360-(x+pab). The rest of the "proof" then falls apart.

Step-by-step explanation:

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4 years ago

he Nassau Bahamas Community College (NBC) claims that students who take statistics spend on average 19 hours a week working. The

Virty [35]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

At the null hypothesis, it is tested if they spend on average 19 hours a week working, that is:

$H_0: \mu = 19$

At the alternative hypothesis, it is tested if they spend more than 19 hours a week working, that is:

$H_1: \mu > 19$

We have the standard deviation for the sample, hence, the t-distribution is used.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Searching the problem on the internet, it is found that the values of the parameters are:

$\overline{x} = 24.2, \mu = 19, s = 12.59, n = 25$

Hence, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.2 - 19}{\frac{12.59}{\sqrt{25}}}$

$t = 2.07$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 25 - 1 = 24 df is of $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

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Answer:

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Step-by-step explanation:

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Answer:

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