Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5
thus,
x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2
The answer is option C
Answer:
x = -5, 1
Step-by-step explanation:
To factor an equation, break the polynomial into two binomials which multiply to make it. Find two numbers that multiply to C and add to B from
.
-1 and 5 multiply to -5 and add to 4.

The zeros are the factors set equal to 0 and solved.
(x+5) = 0
x=-5
(x-1) = 0
x=1
Answer:
x=121
Step-by-step explanation:
because 180-121=59 and 180-59=121
You would have to multiply all the numbers. 4 X 3, 4 X 2, 3 X 2, the answer I got was 36.