The first thing we must do for this case is to define a variable.
We have then:
x: number of years before the Russo-Japanese conflict began
We write now the inequality that models the problem.
We know that the conflict began in the year 1904, therefore, all the previous years are given by:
x <1904
Answer:
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
x <1904
Answer:
its between
Step-by-step explanation:
1.5 and 4.5 cubic inches
Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)
The price of one bag of popcorn is $3.75
Step-by-step explanation:
Let,
x represent the cost of a bag of popcorn
y represent the cost of a drink.
According to given statement;
4x+12y=30 Eqn 1
x+6y=11.25 Eqn 2
Multplying Eqn 2 by 2
Subtracting Eqn 3 from Eqn 1
Dividing both sides by 2
4x+12y=30 and x+6y=11.25 can be used to find the price of one bag of popcorn and the price of one drink.
The price of one bag of popcorn is $3.75
Keywords: linear equation, elimination method
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