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ivolga24 [154]
3 years ago
5

A new product is increased from $5 to $6. What is the percent of change?

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
20% I hope this helps!!!
Sati [7]3 years ago
3 0
$6 - $5 = $1

1/5 * 100 = 20%

answer: percent of change is 20%
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Suppose that a basketball player can score on a particular shot with probability .3. Use the central limit theorem to find the a
Rom4ik [11]

Answer:

(a) The probability that the number of successes is at most 5 is 0.1379.

(b) The probability that the number of successes is at most 5 is 0.1379.

(c) The probability that the number of successes is at most 5 is 0.1379.

(d) The probability that the number of successes is at most 11 is 0.9357.

→ All the exact probabilities are more than the approximated probability.

Step-by-step explanation:

Let <em>S</em> = a basketball player scores a shot.

The probability that a basketball player scores a shot is, P (S) = <em>p</em> = 0.30.

The number of sample selected is, <em>n</em> = 25.

The random variable S\sim Bin(25,0.30)

According to the central limit theorem if the sample taken from an unknown population is large then the sampling distribution of the sample proportion (\hat p) follows a normal distribution.

The mean of the the sampling distribution of the sample proportion is: E(\hat p)=p=0.30

The standard deviation of the the sampling distribution of the sample proportion is:

SD(\hat p)=\sqrt{\frac{ p(1- p)}{n} }=\sqrt{\frac{ 0.30(1-0.30)}{25} }=0.092

(a)

Compute the probability that the number of successes is at most 5 as follows:

The probability of 5 successes is: p=\frac{5}{25} =0.20

P(\hat p\leq 0.20)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.20-0.30}{0.092} )\\=P(Z\leq -1.087)\\=1-P(Z

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 5 is 0.1379.

The exact probability that the number of successes is at most 5 is:

P(S\leq 5)={25\choose 5}(0.30)^{5}91-0.30)^{25-5}=0.1935

The exact probability is more than the approximated probability.

(b)

Compute the probability that the number of successes is at most 7 as follows:

The probability of 5 successes is: p=\frac{7}{25} =0.28

P(\hat p\leq 0.28)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.28-0.30}{0.092} )\\=P(Z\leq -0.2174)\\=1-P(Z

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 7 is 0.4129.

The exact probability that the number of successes is at most 7 is:

P(S\leq 57)={25\choose 7}(0.30)^{7}91-0.30)^{25-7}=0.5118

The exact probability is more than the approximated probability.

(c)

Compute the probability that the number of successes is at most 9 as follows:

The probability of 5 successes is: p=\frac{9}{25} =0.36

P(\hat p\leq 0.36)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.36-0.30}{0.092} )\\=P(Z\leq 0.6522)\\=0.7422

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 9 is 0.7422.

The exact probability that the number of successes is at most 9 is:

P(S\leq 9)={25\choose 9}(0.30)^{9}91-0.30)^{25-9}=0.8106

The exact probability is more than the approximated probability.

(d)

Compute the probability that the number of successes is at most 11 as follows:

The probability of 5 successes is: p=\frac{11}{25} =0.44

P(\hat p\leq 0.44)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.44-0.30}{0.092} )\\=P(Z\leq 1.522)\\=0.9357

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 11 is 0.9357.

The exact probability that the number of successes is at most 11 is:

P(S\leq 11)={25\choose 11}(0.30)^{11}91-0.30)^{25-11}=0.9558

The exact probability is more than the approximated probability.

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3 years ago
Jake gave the cashier $50 to pay for 5 pairs of jeans. The cashier gave him
levacccp [35]

Answer:

8.85

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The area of a square field is 169 sq.cm.Its each side is
Sergeeva-Olga [200]
Each side is 13cm
the square root of 169 is 13
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Jack and Jill live 345 miles apart from one another. They want to meet for lunch and agree to leave the
Novosadov [1.4K]

It will take them 3 hours to meet

Step-by-step explanation:

The given is:

  • Jack and Jill live 345 miles apart from one another
  • They want to meet for lunch and agree to leave the  same time, drive toward each other, and meet somewhere along the route
  • Jack's average rates 60 mph
  • Jill's average rate is 55 mph

We need to find how long it will take them to meet

Distance = Speed × Time

∵ They will drive toward each other at the same time and meet

   each other somewhere

- That means they will drive for the same time

∵ Jack's average rates 60 mph for t hours

∴ Jack will drive a distance = 60 × t = 60 t  miles

∵ Jill's average rate is 55 mph for t hours

∴ Jill will drive a distance = 55 × t = 55 t  miles

∵ The distance between Jack and Jill is 345 miles apart

- Add their distance above and equate the sum by 345

∴ 60 t + 55 t = 345

∴ 115 t = 345

- Divide both sides by 115

∴ t = 3 hours

It will take them 3 hours to meet

Learn more:

You can learn more about the word problems in brainly.com/question/3950386

#LearnwithBrainly

5 0
3 years ago
Please help me fast I need to finish!!!!!!
ioda

Answer:

ans: The line passes through the point (0,13)

Step-by-step explanation:

(0,13) is Y-intercept

4 0
2 years ago
Read 2 more answers
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