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Shtirlitz [24]
3 years ago
13

4 3. Brodie has a bag of mixed fruit snacks. In the bag, there are 8 cherry fruit snacks and 12 strawberry fruit snacks. What is

the ratio of strawberry to cherry? b (answer should be in simplest form)​
Mathematics
2 answers:
Greeley [361]3 years ago
5 0

Answer: simplified ratio would be 3:2

Step-by-step explanation: the ratio would be 12:8

loris [4]3 years ago
5 0

Answer:

2-3, 2 to 3, or 2:3

Step-by-step explanation:

You might be interested in
Jack's train arrived at the station at 8:30 in the evening. The train ride was 2 hours and 10 minutes.
Taya2010 [7]

Answer:

6:20 PM

Step-by-step explanation:

They got there at 8:30 PM, and 2 hours and 10 minutes prior would have been 6:20 PM.

6 0
3 years ago
Please helpppppp!!!!!
azamat
Let they meet after second car travels for x hours'
let v be the speed  of second car and V be speed of first car.
Then time taken by first car=x+2
V(x+2)=vx (distance covered is same.)
\frac{v}{V} = \frac{x+2}{x} 
subtract 1 from both sides
 \frac{v-V}{V} = \frac{2}{x} 
v-V= \frac{2V}{x}


4 0
4 years ago
Write the coordinates​
lesantik [10]

Answer: C- 4,3 D- 9,4 E- 4,5 F- 1,4

Step-by-step explanation:

6 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
Paul was making some brownies and cupcakes for his school fundraiser. If the brownies needed 4.8 cups of sugar and the cupcakes
ArbitrLikvidat [17]

Answer:

10 cups in total.

Step-by-step explanation:

4.8+5.2= 10.00

add the .2 to the 4.8 you get get 5 then add 5.0+5.0

8 0
3 years ago
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