Answer:
nuclear <u>fussion</u> occurs in star's core that combines elements to make BIGGER elements.
Explanation:
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Answer:
Cyanobacteria
Explanation:
Cyanobacteria were the first photosynthetic autotrophs that used water molecules as the source of electrons. Cyanobacteria were the first autotrophs that performed oxygenic photosynthesis and carried out the splitting of water.
The process of splitting water released oxygen as a gas (O2) which was released in the atmosphere of the earth as a by-product. This led to the accumulation of oxygen in the atmosphere. Some cyanobacteria can fix nitrogen and have specialized cells called heterocyst which serve as the site for nitrogen fixation.
Answer:
See below
Explanation:
Do not keep the tap running, when washing your hands.
Do not shower every day.
When showering, get in, shut the tap down. While still wet in the shower, but without the water running, start to apply soap and shampoo. Wait a bit and the start the water again to wash it all off. Get out asap.
Do not keep the hose running, when cleaning your car.
Preferably, do <em>not</em> use a hose, but use a broom, to clean the driveway or sidewalk.
Cover the swimming pool, in order to reduce extensive evaporation.
Check for leaks in pipes, hoses, (dripping) faucets and couplings.
If at all possible, reuse wastewater as much as you can.
<span>The human tympanic membrane or eardrum is a thin, concave membrane stretched across the inner end of the external auditory canal much like the skin covering the top of a drum. The eardrum marks the border between the outer ear and middle ear. ... The middle ear transmits sound from the outer ear to the inner ear.
Answer would be </span>
<span> tympanic membrane or eardrum</span>
Answer: The probability of obtaining an individual who is CcmmLLPp 1/32.
Explanation: This can be achieved by crossing similar genes to obtain individual probability as shown in the attached image.
When you cross Cc in the first genotype with CC in the second genotype, the following probabilities will be obtained;
P (CC) = ¾, P(Cc) = ¼.
Similarly, crossing Mm with mm, we get;
P (Mm) = ½, P (mm) = ½
Crossing Ll with Ll, we get
P (LL) = ¼, P (Ll) = ½, P (ll) = ¼
Crossing PP with pp, we get
P (Pp) = 1
Therefore, the probability of individual with genotype CcmmLLPp will be;
P (Cc) x P (mm) x P (LL) x P (Pp)
= ¼ x ½ x ¼ x 1
= 1/32
