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ella [17]
2 years ago
15

What is the slope of a line perpendicular to the line whose equation is Y=2x+5?

Mathematics
1 answer:
Oksanka [162]2 years ago
8 0
B. slope is -1/2

This is because the m-value aka the slope is always the reciprocal if the line is perpendicular
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If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

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We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

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So the ODE has solution

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which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

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4 0
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Read 2 more answers
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