Give me 8 mins i will answer in the comments
You distribute the number outside the parenthesis from the inside like the 3 to the q and the 3 to the 1 then the -4, add 1 and -4 which becomes -3 but then leave the one with the variable so it becomes 3q-3. do the same for each problem and the one with the fraction i suggest converting it to decimals so it's easier.
x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y
