Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is e
qual to thirty-eight.
29 and 31
39 and 41
49 and 51
2 answers:
2 consecutive odd numbers....x and x + 2
3/7x + 1/3(x + 2) = 38
3/7x + 1/3x + 2/3 = 38
3/7x + 1/3x = 38 - 2/3....multiply by common denominator of 21
9x + 7x = 798 -14
16x = 784
x = 784 / 16
x = 49
x + 2 = 49 + 2 = 51
ur numbers are 49 and 51
I think the answer is 29 and 31
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