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marusya05 [52]
3 years ago
15

Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is e

qual to thirty-eight.
29 and 31
39 and 41
49 and 51
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0
2 consecutive odd numbers....x and x + 2

3/7x + 1/3(x + 2) = 38
3/7x + 1/3x + 2/3 = 38
3/7x + 1/3x = 38 - 2/3....multiply by common denominator of 21
9x + 7x = 798 -14
16x = 784
x = 784 / 16
x = 49

x + 2 = 49 + 2 = 51

ur numbers are 49 and 51

ch4aika [34]3 years ago
4 0
I think the answer is 29 and 31

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P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx

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                                   =\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\

                                   =-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

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