What is the solution for the system of equations x+y=2 and x-y=4

1 answer:

5 0

X+y=2 (label equation one)
x-y=4 (label equation two)

y=-x+2 (equation one rearranged, label this equation equation three)

sub 3 into 2
x-(-x+2)=4
x+x-2=4
2x-2=4
2x=6
x=3
sub x=3 into equation one

3+y=2
y=-1

therefore x=3 and y=-1

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a. Slope of WZ = -2.25; Slope of WX = 5

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<h3>Slope of a Segment</h3>

Slope = change in y/change in x

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$WZ = \sqrt{(3 - (-1))^2 + (-7 - 2)^2}\\\\\mathbf{WZ = \sqrt{97} }$

$WX = \sqrt{(-5 -(-1))^2 + (7 - 2)^2}\\\\\mathbf{WX = \sqrt{41} }$

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