Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
The line x = -11.4 is perpendicular to the x-axis and contains point
(-11.4 , 12.8)
Step-by-step explanation:
Let us revise the equations of the vertical lines and horizontal lines
- The vertical line is a line parallel to y-axis
- The x-coordinates of all points lie on the line are equal
- The equation of the vertical line basses through point (a , b) is x = a
- The horizontal line is a line parallel to x-axis
- The y-coordinates of all points lie on the line are equal
- The equation of the horizontal line passes through point (a , b) is y = b
- The vertical line and the horizontal line are perpendicular to each other when intersect each other
∵ The line is perpendicular to the x-axis
∴ The line is a vertical line
∴ The equation of the line is x = a, where a is the x-coordinate
of any point lies on the line
∵ The line contains point (-11.4 , 12.8)
∵ The x-coordinate of the point is -11.4
∴ a = -11.4
∴ The equation of the line is x = -11.4
The line x = -11.4 is perpendicular to the x-axis and contains point
(-11.4 , 12.8)
Learn more:
You can learn more about the linear equation in brainly.com/question/13168205
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225998 225988
I believe it is the tenths place
(the bold digits)
Answer:
The answer is 3/4 because 2/4 + 1/4 = 3/4.
