Answer:confounding variable
Step-by-step explanation:
Answer:
The number is 12
Step-by-step explanation:
[] First, let's turn all these words into something mathematical. N will equal "my number"
-><u> If you add 12 to my number</u> and then multiply the result by 3, you will get 64 more than two-thirds of my number.
-> n + 12 <u>and then multiply the result by 3</u>, you will get 64 more than two-thirds of my number.
-> 3(n + 12), you will get 64 more than <u>two-thirds of my number</u>.
-> 3(n + 12) = <u>64 more than</u> 
-> 3(n + 12) = 64 + 
[] Phew, okay. Now it is something we can solve and less scary;
[Given]
3(n + 12) = 64 + 
[Distribute]
3n + 36 = 64 + 
[Multiply both sides by 3]
9n + 108 = 192 + 2n
[Subtract 108 and 2n from both sides]
7n = 84
[Divide both sides by 4]
n = 12
Have a nice day!
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- Heather
The best and most correct answer among the choices provided by your question is the third choice or letter C "<span>commutative property of addition."
</span>The word "commutative" comes from "commute" or "move around", so theCommutative Property<span> is the one that refers to moving stuff around. For </span>addition<span>, the rule is "a + b = b + a"; in numbers, this means 2 + 3 = 3 + 2. For multiplication, the rule is "ab = ba"; in numbers, this means 2×3 = 3×2.</span>
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Answer:
The question is not complete.
Step-by-step explanation:
Answer:
Since we know that ΔPQR is a right triangle, we can also asume that:
sin R = cos P = 3/5
So the answer is (d).
* This formular can also be applied to other right triangles.
In a right triangle, sine of one acute angle will always be equal to cosine of the other acute angle.
And we can check this by actually finding cos P using the lengths of the sides, by calculating PR first:
PR = √(PQ² + RQ²) = √(12² + 16²) = 20
=> cos P = PQ/PR = 12/20 = 3/5