1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dusya [7]
2 years ago
15

Find the area of this circle

Mathematics
1 answer:
nekit [7.7K]2 years ago
8 0

Answer:

28.26

Step-by-step explanation:

multiply 3.14 by 3 squared or 9

You might be interested in
Find the Least Common Denominator. Then, express each fraction using the Least Common Denominator.
Nataly_w [17]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
simplify the following polynomial expression. <img src="https://tex.z-dn.net/?f=%285x%5E%7B3%7D%20%2B4x%5E%7B2%7D%20%2B6x-3%29%2
FrozenT [24]
Here is the answer hope it helps

7 0
3 years ago
A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su
dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

<em>H</em>₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }

Given:

\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86

Compute the value of the test statistic as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70

Thus, the value of the test statistic is 4.70.

7 0
3 years ago
2m/(2m 3)-(2m)/(2m-3)=1how many extraneous solutions does the equation have?
Slav-nsk [51]
\frac{2m}{2m+3} - \frac{2m}{2m-3} =1 \\  \frac{2m(2m-3)-2m(2m+3)}{4m^2-9} =1 \\  \frac{4m^2-6m-4m^2-6m}{4m^2-9} =1 \\  \frac{-12m}{4m^2-9} =1 \\ -12m=4m^2-9 \\ 4m^2+12m-9=0 \\ m=0.6213 \ or \ m=-3.6213
For m = 0.6213, \frac{2(0.6213)}{2(0.6213)+3} - \frac{2(0.6213)}{2(0.6213)-3} \\  \frac{1.2426}{4.2426} - \frac{1.2426}{-1.7574} =0.2929+0.7071=1
For m = -3.6213, \frac{2(-3.6213)}{2(-3.6213)+3} - \frac{2(-3.6213)}{2(-3.6213)-3} \\ \frac{-7.2426}{-4.2426} - \frac{-7.2426}{-10.2426} =1.7071-0.7071=1
Therefore, the equation has no extraneous solution.
4 0
3 years ago
9 is 25% of what number?
White raven [17]
The answer is 46 because 9*4=36.
7 0
3 years ago
Other questions:
  • In which of the scenarios can you reverse the dependent and independent variables while keeping the interpretation of the slope
    9·2 answers
  • What is the equation in point-slope form of the line that passes through the point (-4, 5) and has a slope of 23?
    11·2 answers
  • 7(5x + 9) = 12 - (x +9)
    15·1 answer
  • The dimensions of a rectangular garden were 3 m by 10 m. When both dimensions were increased by equal amounts, the area of the g
    7·1 answer
  • FAST PLEASE HELP MEEE: At a certain high school, 35 students play only stringed instruments, 10 students play only brass instrum
    6·1 answer
  • Determine slope and y-intercept <br> Use the following table to answer questions #19 and #20.
    10·1 answer
  • I'm begging someone please help pleasedeeeeeeeeeeeeee PLEASEEWW SOMEONE I REALLY NEED HELPPP PLEASEEEEEEE​
    5·1 answer
  • The following dot plot represents a random sample of elementary students and the number of children that live in their home. If
    12·2 answers
  • someone please help, i don’t understand this and i’m stuck. this is my last homework i need to do for today. if you can help tha
    12·1 answer
  • How can 1% of 600 be used to determine 36% of 600? Enter your answers in the boxes to correctly complete the statement.
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!