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Novosadov [1.4K]
3 years ago
5

State if the triangles in each pair are similar. If so, state how you know they are similar

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

c) similar by the AA rule

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6 + (-9) - (-4) - 3 <br> help
Grace [21]

<em>Hi</em><em>!</em>

<em>Answer</em><em>:</em>

<em>6</em><em> </em><em>+</em><em> </em><em>(</em><em>-9</em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>=</em>

<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>-</em><em> </em><em>b</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>+</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>-6</em><em> </em><em>+</em><em> </em><em>4b</em>

<em>=</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>6</em>

<em>I hope I helped you! Good luck at school! </em>

7 0
3 years ago
Use the function below to find F(3) f(x)=1/4^x
Harman [31]
There is no function below. 
5 0
3 years ago
Read 2 more answers
What expressions are equivalent to j+j+2k
Nookie1986 [14]

Answer:

athe answer is 2( j t k) hope it helped

3 0
3 years ago
A box contains 300 raffle tickets. Only 15 tickets are winning tickets. What is the
Roman55 [17]

Answer:

5%

Step-by-step explanation:

15/300 = 0.05

5%

3 0
3 years ago
Use the diagram of point O. What is the length of OY to the nearest 10th of an Inch? XZ = 10 and OX= 10
Lady bird [3.3K]

From the diagram above,

XZ = 10 in and OX = 10 in

we are to find length of OY

XZ is a chord and line OY divides the chord into equal length

Hence, ZY=YX= 5 in

Now we solve the traingle OXY

To find OY we solve using pythagoras theorem

(Hyp)^2=(Opp)^2+(Adj)^2

applying values from the triangle above

\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}

Therefore,

Length of OY =

5\sqrt[]{3}

8 0
1 year ago
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