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3 years ago

5

Point A is at (3, 2.5) and point B is at (3, 1.4) on a coordinate grid. The distance between the two points is ____. Input numbe

rs and decimal point only, such as 5.8.
HELP im fed up with coordinate grids already :(

@Qwerty99

1 answer:

andriy [413]3 years ago

5 0

The points have the same x-coordinate, so they lie on a horizontal line. The distance between them is the difference between their y-coordinates.

2.5 - 1.4 = 1.1

The distance between the two points is 1.1

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Consider the rectangle enlargement. Pls answer the three questions I will mark brainliest!!

Alenkasestr [34]

Answer:

Perimeter of the original Rectangle is

2(4.5+4.3)=2×8.8= <u>17.6</u><u> </u><u>mm</u>

Side length of the enlarged rectangle is

$\frac{4.5}{4.3} = \frac{24.3}{x} \\ x = \frac{24.3 \times 4.3}{4.5} \\ \boxed{x = 23.22 \: mm}$

Perimeter of the enlarged rectangle

2(24.3+23.22)= 2×47.52= <u>95.04 mm</u>

7 0

3 years ago

Factor each completely. <br><br>10a² - 9a + 2 <br><br>

Sophie [7]

Answer:

a= $\frac{2}{5}$ or $\frac{1}{2}$

Step-by-step explanation:

Equate the equation to zero

$10a^{2}$ -9a+2=0

$10a^{2}$ -5a-4a+2=0

5a(2a-1)-2(2a-1)=0

Write out the factors

(5a-2)(2a-1)=0

Then equate each factor to zero

5a-2=0 OR 2a-1=0

5a=2 OR 2a=1

a= $\frac{2}{5}$ OR a= $\frac{1}{2}$

a= $\frac{2}{5}$ or $\frac{1}{2}$

3 0

3 years ago

1. Calculate the value of x in the following diagram. 53 - Y IN Q 5x 18

777dan777 [17]

Answer:

x = 7

Step-by-step explanation:

QY = 5x

YZ = 18

QZ = 53

Thus:

QY + YZ = QZ (segment addition postulate)

5x + 18 = 53

5x = 53 - 18 (subtraction property of equality)

5x = 35

Divide both sides by 5

x = 7

5 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

Brainliest??????????????????????????????

Nitella [24]

Step-by-step explanation:

Given

f(x) = 3x² + 9

g(x) = 5x

(fog)x = f ( 5x)

= 3 ( 5x) ² + 9

= 3 * 25x² + 9

= 75x² + 9

Hope it will help :)

7 0

3 years ago