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3 years ago

What is the price of discount is applied #6,8,10

Mathematics

1 answer:

son4ous [18]3 years ago

5 0

6. $14*0.045= $0.63
7. $7 *0.0625= $ 0.4375
8. $9 *0.7= $6.30

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What is the x-intercept of 5y=10-4x

Advocard [28]

The x intercept is 2.5

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3 years ago

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When the sun's angle of elevation is 76°, a tree casts an 18-foot shadow on the ground. Find the length of the tree to the neare

Yanka [14]

Answer:

56.5 ft

Step-by-step explanation:

See the attached figure which represents the explanation of the problem.

We need to find the length of the tree to which is the length of AD

From the graph ∠BAC = 90° and ∠ABD = 76°, AB = 18 ft

At ΔABD:

∠BAD = ∠BAC - ∠DAC = 90° - 4° = 86°

∠ADB = 180° - ( ∠BAD + ∠ABD) = 180 - (86+76) = 180 - 162 = 18°

Apply the sine rule at ΔABD

∴ $\frac{AB}{SinD} =\frac{AD}{sinB}$

∴ 18/sin 18 = AD/sin 76

∴ AD = 18 * (sin 76)/(sin 18) ≈ 56.5 (to the nearest tenth of a foot)

So, The length of the tree = 56.5 ft.

The answer is 56.5 ft

3 0

2 years ago

How to do this? (#21 and #23)

Readme [11.4K]

Answer:

$\large\boxed{21.\ g(x)=f(x-2)+1\to g(x)=\log_3(x-2)+1}\\\\\boxed{22.\ g(x)=f(x)-4\to g(x)=3^x-4}\\\\\boxed{23.\ g(x)=-f(x)\to g(x)=-\log_{\frac{1}{2}}x}$

Step-by-step explanation:

f(x) + n - shift the grapf n units up

f(x) - n - shift the grapf n units down

f(x + n) - shift the grapf n units to the left

f(x - n) - shift the grapf n units to the right

-f(x) - reflection about the x-axis

f(-x) - reflection about the y-axis

============================================

Look at the picture.

$21.\\f(x)=\log_3x\\\\g(x)=\log_3(x-2)+1$

move the graph 2 units to the right and 1 unit up

$22.\\f(x)=3^x\\\\g(x)=3^x-4$

move the graph 4 units down

$23.\\f(x)=\log_{\frac{1}{2}}x\\\\g(x)=-\log_{\frac{1}{2}}x$

reflection the graph about the X axis.

4 0

3 years ago

Read 2 more answers

Which account has the highest effective annual interest rate? Account 1: Interest is compounded quarterly at an annual rate of 4

LenKa [72]

Answer:

Account 1 has the highest effective annual interest rate (0.042666142)

Step-by-step explanation:

Hi, to answer this question we have to apply the Effective Annual Interest Rate formula:

EAIR = [(1+r/n)^n ]-1

Where:

r = nominal interest rate

n = number of periods

If interest is compounded annually, then n = 1; if semi-annually, then n = 2; quarterly, then n = 4; monthly, then n = 12

SO:

Account 1: Interest is compounded quarterly at an annual rate of 4.20%.

EAIR = [(1+r/n)^n ]-1 = [(1+(4.20/100)/4)^4 ]-1 = 0.042666142

Account 2: Interest is compounded monthly at an annual rate of 4.15%.

EAIR = [(1+r/n)^n ]-1 = [(1+(4.15/100)/12)^12 ]-1 =0.042298535

Account 3: Interest is compounded semiannually at an annual rate of 4.10%

EAIR = [(1+r/n)^n ]-1 = [(1+(4.10/100)/2)^2]-1 = 0.04142025

Account 4: Interest is compounded annually at a rate of 4.25%.

EAIR = [(1+r/n)^n ]-1 = [(1+(4.25/100)/1)^1 ]-1 = 0.0425

Since:

0.042666142 (1) < 0.0425 (4) < 0.042298535(2) <0.041420258(3)

Account 1 has the highest effective annual interest rate 0.042666142

7 0

3 years ago

What is the value of x?

Fynjy0 [20]

Answer:

Step-by-step explanation:

x+1+4=2x+3

x+5=2x+3

Subtract x from both sides:

5=x+3

Subtract 3 from both sides:

x=2

Hope this helps!

5 0

3 years ago