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Kaylis [27]
3 years ago
7

What is the price of discount is applied #6,8,10

Mathematics
1 answer:
son4ous [18]3 years ago
5 0
6.  $14*0.045= $<span>0.63
7.   $7 *0.0625= $ </span>0.4375
8.  $9 *0.7= $6.30

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A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
Please answer! I’m desperate lol
WARRIOR [948]

Answer:

a

Step-by-step explanation:

just did this last period

8 0
2 years ago
Read 2 more answers
Mark bought 12 boxes of paper clips and 10 packages of index cards for a
Nata [24]

Answer:

paper clips = $1.85

index cards = $3.95

Step-by-step explanation:

Mark

12 paper clips = x

10 index cards = y

$61.70 total

Janice

15 paper clips = x

7 index cards = y

$55.40 total

12x + 10y = 61.70

15x + 7y   = 55.40

*** you want to cancel out one of the letters

(12x + 10y = 61.70) * -7

(15x + 7y   = 55.40) * 10

-84x -70y = -431.9

150x + 70y = 554.0

150x + 70y = 554.0

-84x -70y = -431.9

66x + 0 = 122.1

66x = 122.1

x = 122.1 ÷ 66

x = 1.85

plug it back in

15(1.85) + 7y   = 55.40

27.75 + 7y   = 55.40

7y   = 55.40 - 27.75

7y = 27.65

y = 27.65 ÷ 7

y = 3.95

8 0
3 years ago
The Sydney cricket ground can contain a football field of approximately 147m by 136m. What distance would be covered by walking
Irina-Kira [14]
The answer is 566m because 147 plus 147 and 136 plus 136 equals 566
7 0
2 years ago
Find the value of n in 2m-3n = 6 and 2m + 6n = 12.​
Nezavi [6.7K]

Answer:

n = 2/3

Step-by-step explanation:

2m - 3n = 6

– 2m + 6n = 12

<u>____-____-___</u>

-9n = -6

n = -6/-9

n = 2/3

Hence, the value of n in the given equations is 2/3.

4 0
2 years ago
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