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docker41 [41]
2 years ago
12

Helpppppppppppppppppppppppp

Mathematics
1 answer:
Nonamiya [84]2 years ago
6 0

Answer:

the answer is - 133

Step-by-step explanation:

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Write the equation in slope-intercept form. 5x+3y=12
Umnica [9.8K]
5x+3y=12
Subtract 5x from both sides
3y=-5x+12
Divide by 3
Y=-5/3x +4
7 0
2 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
Please help me! i dont know what to do... And my weekend depends on you
ludmilkaskok [199]
2) 5.3
3) -6
4) -6
5) 6
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3 years ago
Fill in the missing values in the formula. What is the variance? 0 3.217 3.522 12.405 148.86
Lerok [7]

Answer: This’s the answer for your question 12.405

6 0
3 years ago
What is the factorization of the polynomial below? -x^2-15x-54
amid [387]
To factor a polynomial we need to find 2 numbers that add up to -15 and multiply into -54.
(-x -18)(x +3) Will be your answer.
8 0
3 years ago
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