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labwork [276]
3 years ago
6

The perimeter of a flower garden with three sides is 46 feet. One side of the garden is 11 feet long. Another side of the garden

is 13 feet long. What is the length of the third side? Enter your answer in the box. feet
Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

<h2>22ft</h2>

Step-by-step explanation:

Step one:

given that the orientation of the garden is a triangular shape(it has three sides)

the perimeter is given as=46ft

one side y=11ft

the second side z= 13ft

let the third side be xft

Step two:

the expression for the perimeter = z+y+x

46=11+13+x

46=24+x

solve for x

x=46-24

x=22ft

Therefore the third side is 22ft long

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ABCD is a quadrilateral inscribed in a circle, as shown below:
malfutka [58]

Answer:

Option 4: <u>(2x + 16)° + (x)° = 180°</u>

Step-by-step explanation:

See the attached figure.

For a quadrilateral inscribed in a circle

The opposite angles are supplementary.

So, ∠D + ∠B = 180°

From the figure:

∠B = x°  and ∠D = (2x+16)°

∴  <u>(2x + 16)° + (x)° = 180°</u>

4 0
3 years ago
Evaluate the expression. (6-2)[(2+3)+4<br> A) 9 <br> B) 13 <br> C) 24<br> D)36
Kipish [7]
(6-2)(2+3)+4

(4)(5)+4

20+4

=24
7 0
3 years ago
Read 2 more answers
ANSWER BOTH FOR 15 POINTS!!!!
aliya0001 [1]

y = kx is the formula for direct variation

8 = k*20

divide by 20

8/20 =k

divide by 4

2/5 =k

y = 2/5 x

formula:  y = 2/5x

b)  y=2/5x

y = 2/5 *7

y = 14/5

or as a mixed number 2 4/5

6 0
3 years ago
I need the answer ASAP! Please help me!
masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Determining the length of BC</u>

From the diagram, it is clear that

  • The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

<u>Determining the length of CD</u>

Given

  • C (8, 10)
  • D (2, -2)

The distance between C(8, 10) and D(2, -2)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}

      =\sqrt{6^2+12^2}

      =\sqrt{36+144}

      =\sqrt{180}

      =\sqrt{36\times 5}

      =6\sqrt{5}

Thus, the length of CD =6\sqrt{5} units

<u>Determining the length of ED</u>

Given

  • E (-8, -4)
  • D (2, -2)

The distance between E(-8, -4) and D(2, -2)

ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}

      =\sqrt{10^2+2^2}

      =\sqrt{100+4}

      =\sqrt{104}

       =\sqrt{26\times \:4}

        =2\sqrt{26}

Thus, the length of ED =2\sqrt{26} units

<u>Determining the length of EB</u>

From the diagram, it is clear that

  • The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

4 0
3 years ago
GUYS I REALLY NEED AN ANSWER TO THIS AND CAN'T GET IT WRONG AND I KEEP GETTING SKEWED ANSWERS like A C D I really need a solid a
maksim [4K]

Answer:

C

Hope this helped!!

4 0
3 years ago
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