Y= 40x+ 50 (i need 20 characters to post this so ignore)
Sqrt(486) - sqrt(24) + sqrt(6)
find the factors of 486 that we can remove from under the square root sign
2 * 243
2 * 3 * 81
2 * 3 * 9 * 9 (we have 2 nines, we can move a 9 outside the sqrt sign)
sqrt(486) = 9 sqrt(6)
Repeating for sqrt(24)
2 * 12
2 * 2 * 6
2 * 2 * 2 * 3 (we can move a 2 outside the sqrt
sqrt(24) = 2 sqrt(6)
Finally, add all 3 terms together
9 sqrt(6) - 2 sqrt(6) + sqrt(6)
8 sqrt(6)
8 times square root of 6 is the final answer
In both cases you may well benefit from graphing the functions.
Do you recognize f(x) = (x + 1)^2 - 1 as a quadratic function, whose graph is that of a parabola that opens up? By comparing this to y = a(x-h)^2 + k, we see that a=1, h= -1 and k = -1. The vertex is at (h,k), which here is the point (-1, -1). This is the minimum value of the function. Thus, the range of this function is [-1, infinity).
Now for the function f(x) = 7x - 11: This is a linear function whose graph is (surprise!) a straight line. When x increases, y increases, without limits to either. Similarly, when x decreases, y decreases.
Thus the range includes all real numbers: (-infinity, infinity).
Answer:
0.006369
Step-by-step explanation:
Given that a test consists of 10 multiple choice questions, each with five possible answers, one of which is correct.
By mere guessing p = probability for a right answer = 1/5 =0.20
There are two outcomes and each question is independent of the other.
X no of questions right is Bin (10,0.20)
the probability that the student will pass the test
= prob of getting more than 60%
=![P(X\geq 6)](https://tex.z-dn.net/?f=P%28X%5Cgeq%206%29)
=0.006369
3/4...there’s no work to show