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2 years ago

13

You are directed to give a heroin addict 30 mg of methadone PO. the medication comes in tablets labeled 20 mg/tablet.How many ta

blets would you give the patient?

1 answer:

Ber [7]2 years ago

6 0

I'm assuming 1.5 tablets

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Someone please help me!

maw [93]

Vas happenin!

The answer is

57 pi ft squared

Hope this helps

-Zayn Malik

3 0

2 years ago

Explain how to use the Pythagorean Theorem to find the missing length of a right triangle.<br>

tino4ka555 [31]

Pythagorean theorem.

a^2+b^2=c^2

This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.

If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?

I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.

6 0

2 years ago

a chef uses 4 3/4 cups of broth for 10 servings of soup.how much broth is is one serving . let x represent amount. 4 3/4/10 =x/1

enyata [817]

Let's firstly convert the mixed fraction to "improper" and then proceed,

$\bf \begin{array}{ccll}
\stackrel{broth}{cups}&servings\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
4\frac{3}{4}&10\\\\
x&1
\end{array}\implies \cfrac{\quad \stackrel{mixed}{4\frac{3}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{4\cdot 4+3}{4}\quad }{x}=\cfrac{10}{1}$

$\bf \cfrac{\quad \stackrel{improper}{\frac{19}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{19}{4}\quad }{\frac{x}{1}}=\cfrac{10}{1}\implies \cfrac{19}{4}\cdot \cfrac{1}{x}=\cfrac{10}{1}\implies \cfrac{19}{4x}=\cfrac{10}{1}
\\\\\\
19=40x\implies \cfrac{19}{40}=x$

6 0

3 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

3 0

2 years ago

Plz HELP I am struggling with this please provide answer and explanation PLZ!!! WILL MARK BRAINLIEST!!!!!!!!!!!!!!

Alexxandr [17]

The answer is 3/1 - the positive one

3 0

3 years ago