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Nataly_w [17]
3 years ago
7

Find the vector equation of the line

Mathematics
1 answer:
just olya [345]3 years ago
6 0

I hope someone seriously helps him :(

Step-by-step explanation:

sorry I couldn't help ya

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A cartographer creates a map of Bucks County with a scale factor of 1 inch = 10 miles. The distance between Quakertown and Selle
Dennis_Churaev [7]
3 inches i think if im wrong then oof
3 0
3 years ago
which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma
slamgirl [31]
The original expression is given by:
 ( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}
 The correct way to rewrite the expression is given by:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})

 For this, we use two properties:

 Associative property:
 The way of grouping the factors does not change the result of the multiplication:
 \frac{2}{3}*(\frac{1}{5}*\frac{5}{2})

 Commutative property:
 
The order of the factors does not vary the product:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
8 0
4 years ago
Hello I am new to Brainly Hope it will help me​
erastovalidia [21]

Answer:

Welcome ganger

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
F(x)=x^2-3x+18 how many distinct real number zeros does f have?
vampirchik [111]

Answer:

None of the distinct real number zeros the function have.

Step-by-step explanation:

Considering the function

f(x)=x^2-3x+18

The zeroes of a function are those values that touches the x-axis. In order to find those values we must

Set  f(x) = 0 in order to find those values

0=x^2-3x+18

\mathrm{Switch\:sides}

x^2-3x+18=0

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=18:\quad x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{-\left(-3\right)+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

As

3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}=3+\sqrt{63}i

so

x=\frac{3+\sqrt{63}i}{2\cdot \:1}

x=\frac{3+3\sqrt{7}i}{2}

x=\frac{3}{2}+\frac{3\sqrt{7}}{2}i

Similarly,

x=\frac{-\left(-3\right)-\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}:\quad \frac{3}{2}-i\frac{3\sqrt{7}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3}{2}+i\frac{3\sqrt{7}}{2},\:x=\frac{3}{2}-i\frac{3\sqrt{7}}{2}

BUT, NONE OF THEM ARE REAL NUMBER ZEROS.

Therefore, none of the distinct real number zeros the function have.

5 0
4 years ago
Which of the following statements is true of the measure of angle E is equal to the measure of angle Y and the measure of F is e
aev [14]

Answer:

b

Step-by-step explanation:

was answer

4 0
3 years ago
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