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pantera1 [17]
3 years ago
13

Use the first step of the three-step process to find the

Mathematics
2 answers:
Maurinko [17]3 years ago
6 0

Answer:

The answer is B. The number of inches is multiplied by 2.54 to find the number of centimetrers.  

Step-by-step explanation:

I just got it right trust me.

Sauron [17]3 years ago
6 0

Answer:

The number of inches is multiplied by 2.54 to find the number of centimetrers.  

Step-by-step explanation:

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Y-4=-2(x-3) in standard form using integers
Brut [27]

Answer:

-2x-6 I think

Step-by-step explanation:

I think that it is -2x-6 because I did -2 and x is -2x and -2 times -3 is 6.

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2 years ago
The path of a high diver is given by y = −94x2 + 249x + 10 where y is the height in feet above the water and x is the horizontal
sammy [17]

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i dont know maybe someone else can help

7 0
3 years ago
State if polygons are similar
Oksana_A [137]

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yea its is

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3 0
2 years ago
The initial water level of a darn is 35 meters and decreases at a rate of 0.7 meters per day.
sdas [7]

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A

Step-by-step explanation:

5 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
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