Since the chance of a flight being on time is 90%. The probability that all of Erica's flights will be on time is B 66%.
To answer the question, we need to know what probability is
<h3>What is probability?</h3>
This is the likelihood for an event to occur. It is given by
P(event) = number of required outcomes/total number of outcomes
Now, given that Erica's travel plans include 4 independent flights. The chance of a flight being on time is 90%. So, P(flight) = 90%. Since they are indepent, we multiply their probability.
<h3>Probability that all of Erica's flights will be on time</h3>
So, the probability that all of Erica's flights will be on time is P(on time) = P(flight) × P(flight) × P(flight) × P(flight)
= [P(flight)]⁴
= (90%)⁴
= (0.9)⁴
= 0.656
≅ 0.66
= 66%
So, the probability that all of Erica's flights will be on time is B 66%.
Learn more about probability here:
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Answer: 0.1714 miles / hour
Step-by-step explanation:
Given the following :
Distance to the store = 3 miles
Time taken to get to store = 12 hours
Time taken to return = 23 hours
The average rate of speed for the trip =?
Average Speed = total distance traveled / total time taken
Total distance traveled = 2 × 3 miles = 6 miles
Total time taken = 12 + 23 = 35 hours
Average speed = 6 miles / 35 hours
Average speed = 0.1714 miles / hour
Answer:
= -6.66..
Step-by-step explanation:
<u> 5 </u> × <u> 8 </u> = <u> 40 </u>
6 1 6
<u> 40 </u> = -6.66666...
6
The sticker price of the car can be calculated by deducting from the msrp (manufacturer's suggested retail price) the sport package price, stereo package price and the destination charge.
sticker price of the car = ($19,150) - ($2500 + $600 + $600)
sticker price of the car = $15,450
<em>Hence, the sticker price of the car is $15,450. </em>
Step-by-step explanation:
making x subject in eq 1
x= (-1-9y)/-14
substituting the value of x in eq 2
17(-1-9y/-14)=7+9y
(-17-153y)/-14=7+9y
-17-153y=-98-126y
-17+98=153y-126y
81=27y
y=3
substituting this value of y in eq 1
-14x=-1-9(3)
-14x=-28
x=2
(x,y) = (2,3)
