Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Answer:
<em>x² + 2x - 15 = 0 </em>
Step-by-step explanation:
- 5 and 3 are zeros of quadratic function.
(x + 5)(x - 3) = 0
<em>x² + 2x - 15 = 0</em>
Its may be A or C
i am not sure just try to help
The answer is B ,, if it's cut into 4 slices so it's equal which you would divide 100 by 4 = 25 :)
Answer:
It rained 1.29 inches in 3 hours
Step-by-step explanation:
<u>Step 1: Make an equation for the word problem</u>
It rained 0.43 inch each hour. What was the total amount of rainfall in 3 hours
0.43n
<u>Step 2: Plug in 3 for n</u>
0.43n
0.43(3)
1.29
Answer: It rained 1.29 inches in 3 hours