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Alexeev081 [22]
2 years ago
5

Select the correct answer from each drop-down menu. f(x) = x2 − 8x + 15 g(x) = x − 3 h(x) = f(x) ÷g(x) h(x) = . The domain of h(

x) is U .
Mathematics
2 answers:
nlexa [21]2 years ago
7 0

Answer:

h(x) = x-5 . The domain of h(x) is (- infinity,3) U (3, infinity)

Step-by-step explanation: plato/edmentum

9966 [12]2 years ago
4 0

Answer:

all of them

Step-by-step explanation:

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Milley wants to solve the following equations using the method of elimination:
timurjin [86]
She should multiply y = x - 2 by -4...that way one x will be -4x and the other will be 4x   and they will cancel out when added.

answer is -4
3 0
3 years ago
PLEASE HELP ME WITH THIS!!!!!!!!
vlabodo [156]

Answer:

(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.

Step-by-step explanation:

The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.

4 0
3 years ago
Statistics
user100 [1]

Answer:

Step-by-step explanation:

The lower bound is 10.5 and the upper bound is 15.9

Hope it helps!

8 0
2 years ago
Given f(x) = 10 - 16/x, find all c in the interval [2,8] that satisfy the mean value theorem
Katen [24]
F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
f'(c)= \frac{f(b)-f(a)}{b-a} in (2,8),
 \frac{16}{c^2} = \frac{f(8)-f(2)}{8-2} ,
 \frac{16}{c^2} = \frac{8-2}{8-2}

4∈[2,8] is the required point.
8 0
3 years ago
Read 2 more answers
What is the product of -15 and -3? <br> A.5 <br> B.-5 <br> C.-18 <br> D.45
Anastaziya [24]
The product of -15 and -3 is d
7 0
3 years ago
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