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babunello [35]
3 years ago
8

I’m confused a little please help

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

m∠E = 60°

Step-by-step explanation:

The given information in the diagram are;

The shape of the drawing, ΔEDF = A right triangle

The length of the hypotenuse side opposite the right angle = 16·√46

The length of the leg adjacent to the reference angle ∠E = 8·√46

By trigonometric ratio, we have;

\dfrac{Adjacent\ leg \ length}{Hypotenuse \ length} = cos\angle E

Plugging in the values gives;

cos\angle E = \dfrac{8 \cdot \sqrt{46} }{16\cdot \sqrt{46} } = \dfrac{1}{2}

∴ m∠E = arccos(1/2)

Using a calculator or from tables or an online trigonometric ratio tool, we have

arccos(1/2) = 60°

∴ m∠E = arccos(1/2) = 60°.

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What two numbers can be multiplied to be -150 and added to be 5
pav-90 [236]
Xy = -150
x + y = 5

     x + y = 5
x - x + y = -x + 5
           y = -x + 5

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                                               -x² + 5x = -150
                                     -x² + 5x + 150 = 0
                       -1(x²) - 1(-5x) - 1(-150) = 0
                                  -1(x² - 5x - 150) = 0
                                               -1            -1
                                        x² - 5x - 150 = 0
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                                                                2(1)
                                        x = 5 ± √(25 + 600)
                                                         2
                                        x = 5 ± √(625)
                                                     2
                                        x = 5 ± 25
                                                 2
                                        x = 2.5 ± 12.5
                                        x = 2.5 + 12.5    or    x = 2.5 - 12.5
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    x + y = 5
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            or

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If you notice very carefully then you will see that the line passes through the points :

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Hence the value of x = 1 when the value of y = - 2 .

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I mean in graphical method we plot points and then join , here identify the joined points and then make the equation .

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