Part A
1 day = 1/4 hours of practice
7 days = 7/4 hours of practice (multiply both sides by 7)
1 week = 7/4 hours of practice
1 week = (4+3)/4 hours of practice
1 week = (4+3)/4 hours of practice
1 week = (4/4)+(3/4) hours of practice
1 week = 1+(3/4) hours of practice
1 week = 1 & 3/4 hours of practice
side note: 1 & 3/4 = 1.75
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Part B
Take the result from part A, and multiply it with 60
So we'll have 60 times 1&3/4 on the left side on the first line, then 60*(1+3/4) on the right side of this same line.
The rest of the lines look like this
(60*1) + (60*3/4)
60 + 60*3/4
60 + 180/4
60 + 45
105 minutes
Answer:
-26.1 , -0.01 , 12% , 1/4 , 3-4
Step-by-step explanation:
Answer:
8 days
Step-by-step explanation:
On day 8, Isabella will save 256 nickels, bringing her total to 510.
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The number of nickels saved on day n is 2^n. The total is 2^(n+1)-2.
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The above can be written down from your knowledge of binary sequences. If you want a more formal development, read on.
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The number of nickels saved on day n is a geometric sequence with first term 2 and common ratio 2. The n-th term of the sequence is ...
an = a1·r^(n-1) = 2·2^(n-1) = 2^n
The sum of n terms of the sequence is ...
S = a1(r^n -1)/(r -1) = 2(2^n -1)/(2-1)
S = 2^(n+1) -2
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We want S > 500, so ...
500 < 2^(n+1) -2
502 < 2^(n+1)
251 < 2^n
log(251) < n·log(2)
n > log(251)/log(2)
n > 7.97 . . . . . . . . 8 days or more to save more than 500 nickels
Answer: Not really sure what you mean by algebra tiles but I do know that x=2.
Answer:
There is not enough here to answer this problem
Step-by-step explanation:
Sorry : (
