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Kipish [7]
2 years ago
13

AB and CD are parallel. EF is the translation of AB. Is EF parallel to CD? Justify. What does this prove about the effect of tra

nslations on parallel lines?
Mathematics
2 answers:
sergij07 [2.7K]2 years ago
8 0
Yes, EF is parallel to CD. Translation is the simple slide of a shape, therefore it doesn't have an effect on parallel lines.
Molodets [167]2 years ago
7 0

Answer with explanation:

It is given that, two segments or two lines, AB and CD are parallel.

 When we translate a line by some numeric value either horizontally right or left vertically up or down,either it will move downward or upward.

So, line AB when translated either Upward or Downward ,becomes EF.

So, translated line EF will be Parallel to  AB.

Also, AB ║CD.------------(1)

As, EF ║AB.--------(2)

From (1) and (2)

EF ║ AB ║CD

⇒Two lines parallel to same line are parallel to each other.

⇒Translated line will be parallel to Original line and the line parallel to original line.

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Butoxors [25]
❅☃ To find a function you need to look at the x values, if one of the same x value is repeated more then once, it is considered a non function.
❅☃ Option A:
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As you can see no repeated values.
Therefore A is already our function but lets look at the others just in case. 
❅☃ Option B
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9 was repeated therefore it is a non function.
❅☃ Option C
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6 was again repeated. Non function.
❅☃ And lastly, D.
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10 was reapted. Non function.
❅☃ Your answer is A
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2 years ago
A cube is 6 feet on each side. What is its volume?
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36ft

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How did life during the Industrial Revolution differ in the North and the South?  

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How did it make life more difficult? How did life during the Industrial Revolution differ in the North and the South?  

In what ways did the Industrial Revolution make life better?

How did it make life more difficult?

Step-by-step explanation:

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The following table gives results from two groups of students who took a nonproctored test. Use a 0.01 significance level to tes
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Original claim is \mu_{1} =\mu_{2}

Opposite claim is \mu_{1} \neq \mu_{2}

Null and alternative hypotheses:

H_{0}:\mu_{1} = \mu_{2}

H_{1} : \mu_{1} \neq \mu_{2}

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

\bar{x_{1}}=70.29

Sx1=22.09

n_{1} = 30

\bar{x_{2}}=74.26

Sx2=18.15

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Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

t=-0.78

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

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