Answer:
Answer:
Step-by-step explanation:
Give letters, as in the attached image.
The triangles ABE and CDE are similars (AAA). In particular 
11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
Answer:
i think it's B, no solutions
Step-by-step explanation:
because they are parallel to each other
9514 1404 393
Answer:
779.4 square units
Step-by-step explanation:
You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.
One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...
A = (1/2)r²sin(α)
Since there are n such triangles, the area of the n-gon is ...
A = (n/2)r²sin(360°/n)
__
For a hexagon (n=6) with radius 10√3, the area is ...
A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units
