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yulyashka [42]
3 years ago
12

PLEASE HELP!

Mathematics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

1. >

2. <

3. =

Step-by-step explanation:

100x8=800, 4*7=28, multiplied by 25 is 700, therefore making 800 greater than 700. Whenever comparing two multiplication problems, multiplying large numbers produces large results, so whichever starts larger will have an end result that is larger. 100 was large and it is smaller to its counter 25.

36 elevens really means 11x36, which is 396. 40 elevens really means 40x11, which is 440 minus 11x3 which is 407. 407 is greater than 396. The same logic applies here as the previous answer, the only difference is that the removal of three elevens is still larger than 36 elevens in this case.

12x24=288, 6x24=144, doubled makes it 288. In this case, the six is half of the twelve to begin with and then is made up for later by the fact that it is doubled.

When I solve math questions like these, I ignore the fact that it doesn't want a mathematical answer, do the math anyway and pull logic from it. (If your teacher checks, do it on a separate piece of paper, and then toss it.)

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Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a
SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

Area_{A}=0.25*Area_{B} (Equation\ 1)\\

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}

put this value into equation 1

Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\  Area_{B}=80\ cm^{2}

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)}  \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm

Now, put the value of length(2B) into equation 3 to know length (1B)

length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm

I really hope this helps you, have a great day.

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Answer:

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Step-by-step explanation:

hope this helps u!!

8 0
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