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3 years ago

PLEASE HELP!

Mathematics

1 answer:

alexdok [17]3 years ago

5 0

Answer:

1. >

2. <

3. =

Step-by-step explanation:

100x8=800, 4*7=28, multiplied by 25 is 700, therefore making 800 greater than 700. Whenever comparing two multiplication problems, multiplying large numbers produces large results, so whichever starts larger will have an end result that is larger. 100 was large and it is smaller to its counter 25.

36 elevens really means 11x36, which is 396. 40 elevens really means 40x11, which is 440 minus 11x3 which is 407. 407 is greater than 396. The same logic applies here as the previous answer, the only difference is that the removal of three elevens is still larger than 36 elevens in this case.

12x24=288, 6x24=144, doubled makes it 288. In this case, the six is half of the twelve to begin with and then is made up for later by the fact that it is doubled.

When I solve math questions like these, I ignore the fact that it doesn't want a mathematical answer, do the math anyway and pull logic from it. (If your teacher checks, do it on a separate piece of paper, and then toss it.)

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The table shows the participation in a school’s debate club during the last four years.

Dominik [7]

Incomplete question, but use the following example as an illustration.

Step-by-step explanation:

Say one person had $200 in a savings account last month and now has $225. That's an increase. The problem is to find the percent of increase in money.

Read more on Brainly.com - brainly.com/question/14791979#readmore

7 0

3 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

2 years ago

Simplify answer as much as possible

AfilCa [17]

U= -1

-9u+6u=-36+39
-3u=3
u=-1

7 0

3 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$