Which of the following situations would most likely find the Pythagorean theorem useful?

Mathematics

2 answers:

ololo11 [35]4 years ago

8 0

Answer:

an engineer calculating where to place a diagonal support

Step-by-step explanation:

an engineer calculating where to place a diagonal support because the Pythagorean theorem is for right triangle situations. In this case the diagonal support would be like the hypotenuse

Aloiza [94]4 years ago

5 0

Answer:

An engineer calculating where to place a diagonal support

Step-by-step explanation:

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DaniilM [7]

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Step-by-step explanation:

first you add all the pencils up which is 12 next take the probably of taking out one of each pencil .4 for green .2 for black and .6 for yellow next you divide the probably for pulling 1 green bye 2 since your pulling out 2

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3 years ago

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omg i swear PLEASE someone actually explain the answer to me, i need help & im desperate. ill give brainliest to whoever exp

Radda [10]

Answer:

Part 1: 19° C

Part 2: decay

Part 3: 11%

Don't drop out!! You'll hurt yourself if you do that! If you feel trapped/stuck, reach out for help from friends and teachers and parents. Find someone who can help you understand what you're learning and teach you. Study extra if you need to. But don't drop out.

Step-by-step explanation:

You've got the initial temperature down: the constant that the function multiplies is the initial condition/number/temperature/population/&tc. since that constant is 19, the initial temperature is 19° C.

However, this is not an exponential growth function. This is an exponential decay function. There are two ways to surmise this:

The context of the problem is a soda can placed in a cooler. The temperature will decrease, right? This means the function is an exponential decay function.
If the function given were an exponential growth function, then the number within parentheses (this is the percentage by which something changes) would be greater than 1. It isn't, and so the function is an exponential decay function

As for the percentage at which it is changing… erm, decreasing… that would be 100 times the difference of 1 – r. Here, r is the number in parentheses. First, let's solve for 1 – r. Here, r is 0.89, so 1 – 0.89 = 0.11, and now we just need to multiply by 100. Why?

Percentages are a fraction of 100. For example, 89% is equal to 0.89 and the fraction $\frac{89}{100}$ . Here, we multiply 0.11 to find the percentage of change. So we have 0.11 × 100 = 11%, and our rate of change is 11%. Thanks to breyanamyers5 who indirectly hinted at my mistake here!