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never [62]
2 years ago
10

The volume of a rectangular prism (shown below) is 48x^3+56x^2+16x Answer the following questions:

Mathematics
1 answer:
pickupchik [31]2 years ago
8 0

Answer:

(a)

Length = 8x\\Width = 3x + 2\\Height = 2x + 1

(b)

P(2) = 640

(c)

Length= 16

Width = 8

Height =5

(d)

Volume = 640

Step-by-step explanation:

Given

P(x) = 48x^3 + 56x^2 + 16x

Solving (a): The prism dimension

We have:

P(x) = 48x^3 + 56x^2 + 16x

Factor out 8x

P(x) = 8x(6x^2 + 7x + 2)

Expand 7x

P(x) = 8x(6x^2 + 4x + 3x + 2)

Factorize

P(x) = 8x(2x(3x + 2) +1( 3x + 2))

Factor out 3x + 2

P(x) = 8x(3x + 2)(2x + 1)

So, the dimensions are:

Length = 8x\\Width = 3x + 2\\Height = 2x + 1

Solving (b): The volume when x = 2

We have:

P(x) = 48x^3 + 56x^2 + 16x

P(2) = 48 * 2^3 + 56 * 2^2 + 16 * 2

P(2) = 640

Solving (c): The dimensions when x = 2

We have:

Length = 8x\\Width = 3x + 2\\Height = 2x + 1

Substitute 2 for x

Length=8*2

Length= 16

Width = 3*2+2

Width = 8

Height = 2*2 + 1

Height =5

So, we have:

Length= 16

Width = 8

Height =5

Solving (d), the volume in (c)

We have:

Volume = Length * Width * Height

Volume = 16 * 8 * 5

Volume = 640

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Answer:

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Step-by-step explanation:

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Answer:

The answer is

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Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

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Answer:

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Step-by-step explanation:

1) Carry over the decimals in each number.

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