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Jlenok [28]
3 years ago
15

Is 8x-2y=2 a direct or inverse variation

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

Neither, why... for it to be direct or inverse variation, the model has to fit either y=k/x or y=kx, it may not have a y-intercept at all if it is inverse variation and it must have a y-intercept of 0 for it to be direct variation.

Step-by-step explanation:

The statement y=2 is quite specific. Because k is positive, y increases as x increases. So as x increases by 1, y increases by 1.5. Inverse Variation: Because k is positive, y decreases as x increases.  yx is a constant number -8. The constant of variation, k , is 23 . Inverse Variation

An inverse variation can be represented by the equation xy=k or y=kx .

That is, y varies inversely as x if there is some nonzero constant k such that, xy=k or y=kx where x≠0,y≠0 .

Suppose y varies inversely as x such that xy=3 or y=3x . That graph of this equation shown.

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Answer:

Note: The full question is attached as picture below

a) Hо : p = 0.71

Ha : p ≠ 0.71

<em>p </em>= x / n

<em>p </em>= 91/110

<em>p </em>= 0.83.

1 - Pо = 1 - 0.71 = 0.29.

b) Test statistic = z

= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]

= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]

= 0.12 / 0.043265

= 2.77360453

Test statistic = 2.77

c) P-value

P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028

P-value = 0.0056

∝ = 0.01

P-value < ∝

Reject the null hypothesis.  There is sufficient evidence to support the researchers claim at the 1% significance level.

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