Question

How much longer is the hypotenuse of the triangle than its shorter leg?

Answer 1

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(AB)^2=(AC)^2+(BC)^2$

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

$(AB)^2=(6)^2+(8)^2$

$AB=\sqrt{(6)^2+(8)^2}$

$AB=10ft$

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

Answer 2

Answer:4FT IS THE RIGHT ANSWER

Step-by-step explanation:

Answer 3

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