The joint variation that is given in the problem above can be expressed as follows:
w = k/d²
where w is the weight, k is the variation constant, and d is the distance from the center of the earth. Substituting the first scenario to obtain the value of k,
160 = k/(4000)²
k = 2.56 x 10^9
Using this value for the second scenario,
w = (2.56 x 10^9) / (8,000)² = 40 lbs
Thus, the weight of the man, 8000 miles above the center of the earth is 40 lbs.
Is this math cause I'm tryna figure it out
There are 3 face cards for each of the 4 suits, leading to a total possible gain of 120, there are 40 other cards leading to a total possible loss of 80.
120 - 80 = 40.
40 / 52 (total number of cards) = about .77
Final Answer:
The expected value of a draw is positive 0.77 points.
Hope I helped :)
Answer:
31/10 or 3 1/10 more miles.
Step-by-step explanation:
=
(17 × 5) - (27 × 2)
2 × 5
