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Ivan
3 years ago
15

The point (–3, –5) is on the graph of a function. Which equation must be true regarding the function?

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0

Answer:

so the correct answer is a. f(-3)=-5.

Step-by-step explanation:


lisov135 [29]3 years ago
6 0
<span>So the question is what does the point (-3, -5) correspond to on the graph of the function. If we have a point on a graph in the Cartesian coordinate system then that point consists of coordinates (x, y). In other words, y=f(x) and x so (x, f(x)) where x is a x-coordinate and y=f(x) is y-coordinate. So if we have a point (-3, -5) the corresponding coordinates are x=-3 and y=f(x)=-5. So it must be true that y=f(-3)=-5. So the correct answer is a. f(-3)=-5.</span>
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What is a exponential function?
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Step-by-step explanation:

An exponential function is a mathematical function of the following form: f ( x ) = a x. where x is a variable, and a is a constant called the base of the function. The most commonly encountered exponential-function base is the transcendental number e , which is equal to approximately 2.71828.

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Find the measure of y in the picture please
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3 years ago
3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

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a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

Operating on the right side:

\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

Solving for h:

\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

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The building is 61.5 m tall

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3 years ago
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Answer:

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Step-by-step explanation:

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