Answer:
y = 4/6x - 4
Step-by-step explanation:
y = mx + b, m = slope and b = y intercept
Rise over run
Rise = +4
Run = +6
This means the slope is 4/6.
The y intercept is at -4.
Now, plug in the numbers for y = mx + b
y = 4/6x - 4
Answer:
<h2>m∠ABD = 20°</h2>
Step-by-step explanation:
If m∠ABC = 40° and BD is the bisector of ∠ABC, then
(1) m∠ABD = m∠DBC
(2) m∠ABC = m∠ABD + m∠DBC
From (1) and (2) we have:
m∠ABC = 2m∠ABD
Therefore
2m∠ABD = 40° <em>divide both sides by 2</em>
m∠ABD = 20°
Answer:
204/325
Step-by-step explanation:
You can work this a couple of ways. We expect you are probably expected to use trig identities.
cos(A) = √(1 -sin²(A)) = 24/25
sin(B) = √(1 -cos²(B)) = 12/13
cos(A -B) = cos(A)cos(B) +sin(A)sin(B) = (24/25)(5/13) +(7/25)(12/13)
= (24·5 +7·12)/325
cos(A -B) = 204/325
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The other way to work this is using inverse trig functions. It is necessary to carry the full calculator precision if you want an exact answer.
cos(A -B) = cos(arcsin(7/25) -arccos(5/13)) = cos(16.2602° -67.3801°)
= cos(-51.1199°) ≈ 0.62769230 . . . . (last 6 digits repeating)
The denominators of 25 and 13 suggest that the desired fraction will have a denominator of 25·13 = 325, so we can multiply this value by 325 to see what we get.
325·cos(A-B) = 204
so, the exact value is ...
cos(A -B) = 204/325
The answer is 16.0 but I’m not entirely sure
Using a linear function, it is found that the costs are given as follows:
- With r rides: C(r) = 20 + 4r.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
Considering the price of admission and the price per ride, the y-intercept is of 20 and the slope is of 4, the cost for r rides is given by:
C(r) = 20 + 4r.
Hence, for 6 rides, the cost is given by:
C(6) = 20 + 4 x 6 = $44.
More can be learned about linear functions at brainly.com/question/24808124
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