1st option, 2nd, 4th and 5th
Answer:
Step-by-step explanation:
A box contains four cards: One card is black on both sides, one card is red on both sides and two cards are black on one side and red on the other side. One card is selected at random and you can see only one side.i) If the side you see is black, what is the probability that the other side is black?ii) If the side you see is black, what is the probability that the other side is red?
Given that:
Number of cards = 4
x = Black on both sides = 1
y = Red on both sides = 1
z = Black on one side, red on one side = 2
.i) If the side you see is black, what is the probability that the other side is black = b
Probability of black
P(x) = 1/4 ; p(b|x) = 1
P(y) = 1/4 ; p(y|x) =
Answer:
61 degrees
Step-by-step explanation:
==>Given ∆MNO,
MO = 18,
MN = 6
m<O = 17°
==>Required:
Measure of <N
==>SOLUTION:
Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c
Where,
Sine A = 17°
a = 6
Sine B = N
b = 18
Thus,
sin(17)/6 = sin(N)/18
Cross multiply
sin(17)*18 = sin(N)*6
0.2924*18 = 6*sin(N)
5.2632 = 6*sin(N)
Divide both sides by 6
5.2632/6 = sin(N)
0.8772 = sin(N)
sin(N) = 0.8772
N = sin^-1(0.8772)
N ≈ 61° (approximated)
You would do x+ (x+1)=137
2x+1=137
Subtract 1 from each side
2x=136
x=68.
Add 1 to 68, since they are consecutive integers.
The answer is 68 and 69
