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klio [65]
3 years ago
7

Which is a complete list of factors of each term in the expression

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0

A factor is one part of a product.

In the given expression first we separate the terms.

here we have two terms: 15 and 20x

factors of first term 15 : since just one number is there so factors of 15 would be 1, 3, 5 and 15

factors of second term 20x: product of 20 and x gives 20x, so factors of 20x are 1,2,4,5, 10,20 and x

Vinvika [58]3 years ago
5 0

The correct answer for this problem is:

A) 15:1,3,5,15 and 20x: 1,2,4,5,10,20,x

This is correct because to be a complete list of factors for each term there has to be the most common factors but also has to have the variable, being x.

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What is the value of ine^4?
Gnoma [55]

Answer:

The value of ln e^4 is 4 so the answer is D 4 P.S i know its right i just took the test

Step-by-step explanation:

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2 years ago
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A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
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3 years ago
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N + 7 &lt; -3<br><br> solve and show work please
Hitman42 [59]

Answer:

n < -10

Step-by-step explanation:

In order to get the variable n by itself subtract 7 from both sides across the inequality

n + 7 < -3

  -7     -7

n   <  -10

4 0
3 years ago
The cost of 2pounds if potatoes is $3.78 what is the constant of proportionality that represents the relationship between the co
Nana76 [90]

Answer:

The constant of proportionality is 1.89

Step-by-step explanation:

2 pounds = $3.78

1 pound = $3.78/2 = $1.89

Cost y is directly proportional to the pound of potato

y = 1.89x

The constant of proportionality is the cost of 1 pound of potato, and it is 1.89

7 0
3 years ago
Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from
Lapatulllka [165]
<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

The area of a triangle is= \frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]

=|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|

=|-54| = 54 square units

The length of AC = \sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}

                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

5 0
3 years ago
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