Y=(1/2 x)-2
My Work:
Say that the slop is "a" and that the y-intercept is "b".
For the slope:
First coordinate equation: -3=-2a+b
Second coordinate equation: -1=2a+b
Combine the equations. -3-(-1)=-2a-(2a)+b-(b)
Break down the parenthesis. -3+1=-2a-2a+b-b
Simplify the equation. -2=-4a
Divide both sides by -4 to get the answer to the slope. a=1/2
For the y-intercept:
Use the second coordinate's equation and the now known slope. -3=-2*1/2+b
Multiply -2 by 1/2 (Order of Operations). -3=-1+b
Add +1 to both sides to cancel the -1. -3+1=b
Finally, solve the solve -3+1 to get the answer to the y-intercept. b=-2
Answer:
9.) 
10.) 
11.)
minutes of calling would make the two plans equal.
12.) Company B.
Step-by-step explanation:
Let <em>t</em> equal the total cost, and <em>m,</em> minutes.
Set up your models for questions 9 & 10 like this:
<em>total cost = (cost per minute)# of minutes + monthly fee</em>
Substitute your values for #9:

Substitute your values for #10:

__
To find how many minutes of calling would result in an equal total cost, we have to set the two models we just got equal to each other.

Let's subtract
from both sides of the equation:

Subtract
from both sides of the equation:

Divide by the coefficient of
, in this case: 

__
Let's substitute
minutes into both of our original models from questions 9 & 10 to see which one the person should choose (the cheaper one).
Company A:

Multiply.

Add.

Company B:

Multiply.

Add.

<em />
X=41 Just S=ubract The 4 from 37 Then Subract X From X And Divide The Whole Thing By -1
Answer:
$16.77
Step-by-step explanation:
6.99*2.4=16.776
The temperature on Tuesday afternoon is below 38 degrees Fahrenheit. As it states in the question the temperature on Tuesday morning was 27 degrees Fahrenheit and rose 10 more degrees at noon. Which makes is 37 degrees Fahrenheit at noon on Tuesday. You get this by taking 27 degrees and adding 10 degrees.