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nevsk [136]
2 years ago
12

For the first year of a new job, you make P70,000. You get an annual raise each year of 3%. Find out total amount of money you w

ill make in 5 years.
Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0

Answer:

P371,639.507

Step-by-step explanation:

First year: 70,000

Second year: 72,100

Third year: 74,263

Fourth year: 76,490.89

Fifth year: 78,785.6167

If you plus them all the total is 371,639.507

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Sedaia [141]

Answer:

1. X > 8

2.  a.  X < 5

Step-by-step explanation:

1. 3x - 8 > 16

    +8.    +8

3x > 24

divide both sides by 3

x >8

2.   2x - 1 < 9

          +1.   +1

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2 years ago
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3 years ago
Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).
Natalija [7]

Answer:

9a^4 b^10(2 +3a^6 b^5)  (2 -3a^6 b^5)

see work below

Step-by-step explanation:

36a^4b^10 - 81a^16b^20

A)  find the GCF

36a^4b^10 = 4*9 a^4b^10  = 2*2*3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

81a^16b^20= 9*9a^16b^20= 3*3*3*3* a*a*a*a*a*a*a*a*a*a*a*a*a*a*a*a                *b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b

The terms that appear in both terms is the GCF.  The terms that remain are inside the parentheses.

The GCF is 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

36a^4b^10 - 81a^16b^20 = 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b *

( 2*2 - 3*3a*a*a*a*a*a*a*a*a*a*a*a b*b*b*b*b*b*b*b*b*b)

Combining like terms

36a^4b^10 - 81a^16b^20 = 9a^4b^10(4-9a^12b^10)

The expression inside the parenthesis can be factored using the difference of squares

let x^2 =4   x =2  

y^2 = 9a^12 b^10   y = 3a^6b^5

(x^2 -y^2) = (x+y)(x-y)

9a^4b^10(4-9a^12b^10) = 9a^4b^10 ( 2+3a^6b^5) ( 2-3a^6b^5)

b) difference of squares  a^2 – b^2 = (a + b)(a – b)

let a^2 = 36a^4b^10

so a = 6a^2b^5

b^2 = 81a^16b^20

b = 9a^8 b^10

a^2 – b^2 = (a + b)(a – b)

36a^4b^10 - 81a^16b^20 = (6a^2b^5 +9a^8 b^10) (6a^2b^5 -9a^8 b^10)

We can factor a 3 a^2 b^5 out of the first term

3 a^2 b^5 (2 +3a^6 b^5) (6a^2b^5 -9a^8 b^10)

3 a^2 b^5 (2 +3a^6 b^5) 3 a^2 b^5 (2 -3a^6 b^5)

Multiply the terms outside the parentheses together

9a^4 b^10(2 +3a^6 b^5)  (2 -3a^6 b^5)

4 0
3 years ago
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Use the zero product property to find the solutions to the equation x^2-13x+30=0
Daniel [21]

We need to solve the zeroes of the given expression x² - 13x + 30 = 0 and we need to apply zero product property.First, we need to identify the two numbers which will result to -13 when added and it will result to 30 when multiplied. These two numbers are -3 and -10. Then, we can proceed with the solution such as:
x² - 13x + 30 = 0
(x-3) (x- 10) =0
From above, we have already the two zero product:
x-3 = 0
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The answers are x1 = 3 and x2 = 10.
8 0
3 years ago
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mariarad [96]
The answer is D, 

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6 0
3 years ago
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