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AURORKA [14]
2 years ago
10

I have asked so many times and no one will answer. :(

Mathematics
1 answer:
andrew-mc [135]2 years ago
4 0

Answer:

1) \frac{1}{2^7} ; 2) 11^7

Step-by-step explanation:

1) Using the Power of a Fraction Rule (\frac{a}{b} )^x = (\frac{a^x}{b^x} ),

(\frac{1}{2} )^7 = (\frac{1^7}{2^7} ), which can just be simplified to \frac{1}{2^7}.

2) Using the Negative Exponent Rule, a^{-x}  = \frac{1}{a^{x}},

(\frac{1}{11} )^{-7} = \frac{1}{\frac{1}{11^7}}, which can be simplified to 11^7.

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HELP!!! WILL BE MARK AS A BRAINLISTTTT!!! Please
jonny [76]
I believe the answer is b
8 0
3 years ago
Please help with this
Setler [38]

Answer:

x = 6

Step-by-step explanation:

The scale factor is

28/8 = 7/2

We take the ratio of the larger side over the smaller side

Using ratios we can find the sides

28         21

----- = ---------

8           x

Using cross products

28x = 21*8

28x =168

Divide each side by 28

28x/28 = 168/28

x =6

7 0
3 years ago
Which formula is correct ?
larisa86 [58]

Answer:

The first answer choice

Step-by-step explanation:

Formula for volume of a rectangular pyramid is V=lwh/3

6 0
2 years ago
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
3 years ago
Change 68/11 into a mixed number.
SpyIntel [72]
\dfrac{68}{11}=\dfrac{66+2}{11}=\dfrac{66}{11}+\dfrac{2}{11}=6+\dfrac{2}{11}
6 0
3 years ago
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