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sertanlavr [38]
2 years ago
13

The 7th term of an AP is 4 and its common difference is -4. What is the first term?

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
8 0

Answer: 28

Step-by-step explanation:

The 7th term of an AP is 4 and its common difference is -4. The 7th term of an arithmetic progression is written as:

a + 6d = 4

where,

a = first term

d = common difference= -4

a + 6d = 4

a + 6(-4) = 4

a - 24 = 4

a = 4 + 24

a = 28

The first term is 28.

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Solve for a.<br><br> a+(−1.2)=−5.5
Oksanka [162]
It is a + (-1.2) = -5.5
= a - 1.2 = -5.5
= a = -5.5 + 1.2
= a = -4.3

In short, Your Answer would be -4.3

Hope this helps!
4 0
3 years ago
Read 2 more answers
Write a function to represent the set of ordered pairs.
77julia77 [94]

Answer:

Option C   f (x) = x^ 2 - 2

Step-by-step explanation:

Note that the relation describing the set of ordered pairs does not change at a costing rate

y_2 -y_1 = 7-2 = 5\\\\y_3 -y_2 = 14- 7 = 7\\\\y_4 - y_3 = 23- 14 = 9

Therefore the relationship is not linear.

However, the exchange rate y_n- y_{n-1} increases by a factor of 2 units when n increases 1 unit. This allows us to conclude that the relationship is quadratic

Note that the following ordered pairs belong to the function

y = x ^ 2

A = {(2, 4), (3, 9), (4, 16), (5, 25)}

The set of ordered pairs that we have is:

B = {(2, 2), (3, 7), (4, 16), (5, 23)}

Note that there is a similarity between both sets of ordered pairs.

In set B the values of y are always 2 units less than the values in y of the set A.

Then we deduce that since the function that models the set A is y = x ^ 2 then the function that contains the ordered pairs of the B set is:

y = x ^ 2 -2

The correct option is option C) f (x) = x^ 2 - 2

8 0
3 years ago
What is the true solution to 3 in 2 + in 8 = 2 in (4x)
11Alexandr11 [23.1K]
The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑(a^{x}) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑(2^{6})
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = 2^{6}
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
         , x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)
5 0
2 years ago
Read 2 more answers
Help? (only people who know what they're doing please)
Temka [501]
X would equal 2.7 //////////////
7 0
2 years ago
Melanie eats 1.5 pounds of cereal each week. Which model below best represents the number of pounds of cereal she eats in .5 wee
Katena32 [7]
For this case, the first thing we must do is define a variable.
 We have then:
 x: number of weeks
 y: amount of cereal that Melanie eats
 We now write the function that models the problem:
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 Then, for 5 weeks we have:
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 Answer:
 
A model that best represents the number of pounds of cereal she eats is:
 
y = 1.5x&#10;
 For 5 weeks we have:
 
y = 7.5 pounds
5 0
2 years ago
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