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AfilCa [17]
3 years ago
9

ASAP! 70 points! Yan has already finished 3/4 of the 45 math problems he was assigned today. Each math problem took him 1 and 4/

5 of a minute to complete. If this pace continues, how much more time, to the nearest minute, will the rest of the problems take him to finish?
A. 18 mins


B. 27 mins


C. 32 mins


D. 43 mins
Mathematics
1 answer:
siniylev [52]3 years ago
7 0
I would help but Can u add a pic or something for more understanding
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Write the equation of the line f.
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Answer:

y = -4

Step-by-step explanation:

This is because any point on that line would have a y coordinate of -4 → e.g. (6, -4), (-2, -4), and it intercepts the y axis at -4.

Hope this helps!

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Simplify.<br> (4a2b)(-2a3b4c2)
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Simple,

just simplify your problem....

4a^{2} * -2a^{3} = -8a^{5} &#10;&#10; (remember "multiplying" exponents adds them)

b* b^{4} = b^{5}

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Making your answer... -8a^{5}  b^{5} c^{2}
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The coordinates of point T are (0,6). The midpoint of ST is (3, -4). Find the coordinates of point S
bezimeni [28]

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S = (-8, 0 )

Step-by-step explanation:

7 0
3 years ago
40 POINTS AVAILABLE
vazorg [7]

Answer:

The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Step 1

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

<em>Find the length of each side of square BCDE</em>

we have that

AB=18\ units

The diagonal DB is  equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}\\ 1,296=2x^{2}\\ 648=x^{2}\\ x=\sqrt{648}\ units

step 3

<em>Find the area of the square BCDE</em>

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

<em>Find the area of the smaller circle</em>

The area of the circle is equal to

A=\pi r^{2}

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
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