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sineoko [7]
3 years ago
5

Estelle is helping at a community food drive by boxing up cans of soup. There are two sizes of boxes, large and small. Estelle f

ills 3 large boxes and 5 small boxes with 170 soup cans total. The boy working next to her fills 4 large boxes and 4 small boxes with 184 soup cans total. How many cans does each small box hold?
Mathematics
2 answers:
podryga [215]3 years ago
4 0

Answer:

The small box contains 21 cans

<em></em>

Step-by-step explanation:

Represent the small box with S and the large with L.

For Estelle:

3L + 5S = 170

For the boy:

4L + 4S = 184

Required

Determine the cans in the small box

3L + 5S = 170 --- (1)

4L + 4S = 184 --- (2)

Divide (2) through by 4

L + S = 46

Make L the subject

L = 46 -S

Substitute 46 - S for L in (1)

3L + 5S = 170

3(46 - S) + 5S = 170

Open bracket

128 - 3S + 5S = 170

128 + 2S = 170

Collect Like Terms

2S = 170-128

2S = 42

Divide both sides by 2

S = 21

<em>Hence, the small box contains 21 cans</em>

crimeas [40]3 years ago
3 0

Answer:

16

Step-by-step explanation:

I just did it

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Rewrite 25 as an exponent.
devlian [24]

Answer: 25 as a exponent is 25^1.

Step-by-step Explanation: To write a exponent, you figure out the main number and how many times the main number is repeating.

Ex: 91x91x91x91x91x91x91

Main number: 91

Repeating how many times: 7

Final answer: 91^7

7 0
3 years ago
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Two angles are supplementary. One angle has a measure of 44 degrees. What is the measure of the other angle?
xxMikexx [17]
If A and B are supplementary angles, then:
A+B=180º


In this case:
A=44º

44º+B=180º
B=180º-44º=136º

Anser: the measure of the other angle is 136º
7 0
3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
4 years ago
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tatuchka [14]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
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Use the figure to write the segment addition postulate, write an equation and solve for x.
Alenkinab [10]

Answer:

5. x = -1

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Step-by-step explanation:

5. AB = 5

BC = 2x + 6

AC = x + 10

AB + BC = AC (segment addition postulate)

5 + 2x + 6 = x + 10 (substitution)

Collect like terms

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Solve for x

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Collect like terms

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Subtract 27 from both sides

6x + 27 - 27 = 39 - 27

6x = 12

Divided both sides by 6

6x/6 = 12/6

x = 2

4 0
3 years ago
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