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ANEK [815]
3 years ago
11

GUYS AND LADIES PLSSSSSSS HELP ME AHHHHHH Im IN 1st grade wat is 1 plus 1

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

answer: 1 + 1 = 2

HAHAHA LOL

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840 students attend Northfield middle school. 65%of students earned a perfect attendance award. How many students didn't earn th
DochEvi [55]

Answer:

546

Step-by-step explanation:

840 x 0.65 = answer .. in this case 546

6 0
3 years ago
If the x is the number, how would you represent 9 more than the number
Roman55 [17]

Answer:

x = x+9

Step-by-step explanation:

well that is the only way you can do it as we do not know about what x is. also, if you meant by x + (x*9), you can represent that as x*10

8 0
3 years ago
The value of πPhone stock has increased 9% each year for the past several years. In 2020, the stock was worth $75. What will the
Iteru [2.4K]

Answer:

2027 = $122.25

2016 = $48

Step-by-step explanation:

Find 1% of 75

75 / 100 = 0.75

multiply by 9

0.75 * 9 = 6.75

So that's $6.75 each year

Now, lets find our answers for 7 years.

6.75 * 7 = $47.25

75 + 47.25 = $122.25

<u>The stock will be $122.25 in 2027</u>

Now for 2016.

$6.75 * 4 = $27

$75 - $27 = $48

<u>The stock was $48 in 2016</u>

4 0
3 years ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
A radio manufacturer believes that the length of life of WPPX model radio is normal with µ=12 years and σ=2.5 years. (a) What pe
kicyunya [14]

Answer:

(a) 5.48%

(b) 17.82 years

(c) 21.19%

(d) 15.21 years

Step-by-step explanation:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

µ=12 years and σ=2.5 years.

(a) What percent of the radios will function for more than 16 years?

For x = 16

z = 16 - 12/2.5

z = 1.6

Probability value from Z-Table:

P(x<16) = 0.9452

P(x>16) = 1 - P(x<16)

1 - 0.9452

= 0.054799

Converting to percentage = 0.054799 × 100

= 5.4799%

Approximately = 5.48%

(b) Suppose the company decides to replace 1% of the radios. Find the length of the guarantee period. i.e. find X.

find the z score of the 99th percentile = 2.326

Hence:z = (x-μ)/σ

2.326 = x - 12/2.5

Cross Multiply

2.326 × 2.5 = x - 12

5.815 = x - 12

x = 12 + 5.815

x = 17.815

Approximately = 17.82 years

(c) What percent of the radios that will fail to satisfy the guarantee period of 10 years? , i.e. less than 10 years?

When x < 10

Hence,

z = 10 - 12/2.5

z = -0.8

Probability value from Z-Table:

P(x<10) = 0.21186

Converting to percentage

0.21186 × 100

= 21.186%

Approximately = 21.19%

(d) If 10% of the radios will function for more than X years, find X.

The z score would be : 100 - 10%

= 90th percentile z score

We find the z score of the 90th percentile = 1.282

Hence:z = (x-μ)/σ

1.282 = x - 12/2.5

Cross Multiply

1.282 × 2.5 = x - 12

3.205 = x - 12

x = 12 + 3.205

x = 15.205

Approximately = 15.21 years

4 0
3 years ago
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