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Vsevolod [243]
3 years ago
12

Please Help Can someone explain where the 4i to the square root of 3 came from?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

note that \sqrt{-1} = i

\sqrt{64-112}

= \sqrt{-48}

= \sqrt{16(3)(-1)}

= \sqrt{16} × \sqrt{3} × \sqrt{-1}

= 4 × \sqrt{3} × i

= 4i\sqrt{3}

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