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emmainna [20.7K]
3 years ago
11

(-5,5)(5,0) help pls need the work shown as well ahaha!

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

Formula to find slope is y2-y1/x2-x1

Chose one ordered pair to be the 2 and the other one to be the 1

I chose the 2nd one to be 2.

Plug in the y-value from the 2nd ordered pair to y2 because its the 2.

Plug in the x-value from the 2nd ordered pair to x2 because its the 2.

Now you have 0-y1/5-x1

Do the same thing but for the 1.

Plug in the y-value from the 1st ordered pair to y1 because its the 1.

Plug in the x-value from the 1st ordered pair to x1 because its the 1.

Now you have 0-5/5--5

In this situation, you have 2 minus signs.

2 minus = 1 positive.

Now you have 0-5/5+5

Simplify.

Now you have -5/10.

Simplify.

-1/2.

Hope this helps!

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Step-by-step explanation:

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3 years ago
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On a typical day flights at a local airport arrive at a rate of 10 every 15 minutes. At this rate how many flights would you exp
Arturiano [62]
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Write the percent as a mixed number in simplest form.<br> 168%
vladimir2022 [97]

Answer:

1 and 17/25

Step-by-step explanation:

First, you make it into a fraction. So because percents are out of 100, it would be 168/100. Then, you take 100 out of it to get a mixed number, 1 and 68/100, and then simplify 68/100 by dividing both sides by the greatest common factor, which is 4. 68/100÷4=17/25. The answer would be 1 and 17/25.

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6 0
3 years ago
A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker
valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

8 0
3 years ago
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