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White raven [17]
3 years ago
5

The height (ft) of an object is launched into the air given by the function h(t)=-6t^2+120t+17 where t is the time in seconds.

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

Object will reach the max height in 10 seconds.

Max. height is 1817.

It will hit the ground in 20 seconds.

Step-by-step explanation:

In order to find the x value which makes the function take its greatest value, you need to take the derivative of the function and equalize the result to 0.

h'(t)=-12t+120=0

t=10

The object will reach its maximum height in 10 seconds.

h(10) (maximum height) = 6.10.10+120.10+17= 600+1200+17=1817

Considering this is a parabola, time in total is two times more than the time passed until reaching the max. height.

10.2=20

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HELP PLEASE I NEED THIS DONE ASAP
Nata [24]

a). 0.45 with a line over the 45 means 0.45454545454545... forever.

It's equivalent to  45/99  which is  <em>5/11</em> .

b). 0.45 with a line over the 5 means 0.455555555... forever.

It's equivalent to (0.4 + 0.555555.../10)

The 0.4 part is  4/10

The 0.5555555555.../10 part is  5/90 .

(4/10) + (5/90) = <em>41/90 </em>

c). 0.45 means 45/100 .  That's <em> 9/20</em> .

I don't think you're supposed to be posting unit test questions on Brainly.

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3 years ago
Solve the system by substitution. Check your solution.
zvonat [6]
B. (9,126)

<span>y + 18 = 16x
=>y=16x-18 
0.5x + 0.25y = 36 (multiply both sides by 4)
=>2x+y = 144
Substitute y=16x-8

=>2x+16x-8=144
=>18x=152
=>x=152/18=9 
y=16x-18
=>y=16(9)-18
=>y=144-18=126 
Answer: x=9 and y=126</span>
4 0
3 years ago
Principal = $ 15000, rate = 10% p.a. and time<br> 21/5 years<br> PLS HELP ASAP
denpristay [2]

Answer:

Simple Interest: A=P(1+rt)

A=15000(1+(0.1*4.2))

A=$21,300

Compound Interest:A=P(1+r/n)^nt

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Step-by-step explanation:

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Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

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dlinn [17]

Answer:

(1,-4)

Step-by-step explanation:

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