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White raven [17]
3 years ago
5

The height (ft) of an object is launched into the air given by the function h(t)=-6t^2+120t+17 where t is the time in seconds.

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

Object will reach the max height in 10 seconds.

Max. height is 1817.

It will hit the ground in 20 seconds.

Step-by-step explanation:

In order to find the x value which makes the function take its greatest value, you need to take the derivative of the function and equalize the result to 0.

h'(t)=-12t+120=0

t=10

The object will reach its maximum height in 10 seconds.

h(10) (maximum height) = 6.10.10+120.10+17= 600+1200+17=1817

Considering this is a parabola, time in total is two times more than the time passed until reaching the max. height.

10.2=20

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The normal to the </span><span>paraboloid at any point is given by:

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Equating the two normal vectors, we have:
</span>
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