Because this is asking for what the y value will be when the x value is 10, we simply replace the 'x' variable with 10.
G(10) = -3(10) + 1
G(10) = -30 + 1
<h3><u>G(10) = -29</u></h3>
Answer:
There's only 1 step. It is the second one, "Multiply 4 by 5 and multiply 4 by 3x"
Step-by-step explanation:
4(5 - 3x) =
4(5) - 4(3x) =
20 - 12x
You can't simplify further, so the second one is the right answer
Hope this helps! :)
Answer:
The answer is
g(x) = (x-3)^3
Step-by-step explanation:
We can easily solve this problem by plotting each equation with a graphing tool or calculator.
Please see attached graph
The correct answer is
g(x) = (x-3)^3
Hello!
1. 2=e-1
First, you switch sides.
Then, you add 1 from both sides of an equation.
Add by the numbers.
, is the correct answer.
_____________________________________________
2. r-3=1
First, you add by 3 both sides of an equation.
Add by the numbers.
, is the correct answer.
__________________________________________________
3. z-6.3=2.1
First, you add by 6.3 both sides of an equation.
Add by the numbers.
, is the correct answer.
____________________________________________________
4. t-9.25=5.5
First, you add by 9.25 both sides of an equation.
Simplify.
, is the correct answer.
____________________________________________________
5. k-32.9=16.5
First, you add 32.9 both sides of an equation
Add by the numbers.
, is the correct answer.
______________________________________________________
Hope this helps!
Have a nice day! :)
:D
-Charlie
Thank you!
<span>Declaring the volume function
double PyramidVolume(double baseLength, double baseWidth, double pyramidHeight){
double baseArea = baseLength * baseWidth;
double vol = ((baseArea * pyramidHeight) * 1/3);
return vol;
}
int main() {
cout << "Volume for 1.0, 1.0, 1.0 is: " << PyramidVolume(1.0, 1.0, 1.0) << endl;
return 0;
}
Defining the function,
include <iostream>
double PyramidVolume(double, double, double);
int main()
{
std::cout << "Volume for 1.0, 1.0, 1.0 is: " << PyramidVolume(1.0, 1.0, 1.0) << std::endl;
return 0;
}
double PyramidVolume(double length, double width, double height)
{
return length * width * height / 3;
}</span>
